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Q: What digit can make 87 to be divisible by 3?

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I don't completely understand the question, but there's a trick: A number is divisible by 3 if and only if the sum of its digits is divisible by 3. This should guide you to an answer.

29 is not divisible by 3 and how any digit will alter that depends on how that digit is to interact with 29.

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.

numbers divisible to 87 = 3, 29, 87

a 3 digit number that is divisible by on is a three digit number that is a multiple of one.

no. it is divisible by 3 (87/3=29)

no

The only 3-digit number that is divisible by 624 is 624.

There are 180 3-digit numbers divisible by five.

1, 3, 29, 87

No single digit determines divisibility by 3.

There are 151 3-digit numbers that are divisible by 6.

the number 3 is divisible by 3

261, 264, or 267

You can find the answer of this question using A.P.(Arithmetic Progression). Its the easiest way. Here's the solution: First 2-digit no. divisible by 3 = 12 Second 2-digit no. divisible by 3 = 15 Last 2-digit no. divisible by 3 = 99 Hence, the 2-digit no.s divisible by 3 form an A.P. with common difference 3 as follows: 12,15,.........................,99 Here, a (First term) = 12 l (Last term) = 99 d (Common difference) = 3 n (No. of terms) = ? Using the formula, l = a + (n-1)d 99 = 12 + (n-1)3 (n-1)3 = 99 - 12 (n-1)3 = 87 n-1 = 87 / 3 n-1 = 29 n = 29 + 1 = 30 Hence, the total no. of 2-digit no.s divisible by 3 are 30.

1002 is the smallest 4 digit number divisible by 3 and 2.

87 is divisible by 1, 3, 29, and 87. 100 is divisible by 1, 2, 4, 5, 10, 20, 25, 50, and 100, therefore the only number divisible by 87 and 100 is 1.

Yes

36360 is a 5 digit number that is divisible by both 3 and 9.

Yes. 87 is divisible by 3 and 29.

None. 3 digit numbers are not divisible by 19 digit numbers.

The 3, to the left.

No. Consider 13 or 23.

Yes.

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